Sunday, May 31, 2015
“The difference between the historian and the poet is not
merely that one writes verse and the other prose…the essential difference is
that the one tells us what happened and the other the sort of thing that would
happen. This is why poetry is at once more like philosophy and more worth while
than history, since poetry tends to make general statements, while those of
history are particular. A ‘general statement’ means one that tells us what sort
of man would, probably or necessarily, say or do what sort of things, and this
is what poetry aims at, though it attaches proper names; a particular statement
on the other hand tells us what Alcibiades, for instance, did or what happened
to him.”
Aristotle, Poetics 1451b3-1
I like how Aristotle likens the poet to the philosopher—so
much for the alleged war between them. However, I’m puzzled by Aristotle’s
reason for thinking that the poet is more like the philosopher than the
historian. Is it really the case that the poet’s business is to tell us what a
certain sort of person would do? Is this what the philosopher is in the
business of doing? Furthermore, the historian does tell us what has happened,
as opposed to what would happen, but the historian also gives us an account of
what happened—viz. an explanation. And isn’t part of the point of learning
history is to know what we would most likely do in similar circumstances?
Monday, May 25, 2015
on whether every thought can be expressed.
It’s obvious that some thoughts are not expressible in
English. Of course, ex hypothesi, I
can’t give you any examples. And there’s no inconsistency whatever in expressing
this fact in English, for even if their genus is expressible in English (viz.
the thoughts which are not expressible in English), it doesn’t follow that
their specific difference is thereby expressible in English.
not either, not both, and not even between.
Let ‘T’ abbreviate ‘true’;
consider:
(1) (x)(Tx v
~Tx)
(1) says that everything is either true or not true. I say
(1) is false for an infinite number or reasons.
Here are five: it’s not true that my cat is either true or not true.
It’s not true that my nostril is either true or not true. It’s not true that a
banana is true or not true. It’s not
true that this italicized sentence is
either true or not true. If you’re not convinced that (1) is not true, I
suggest that you consider each and every natural number n, and you’ll see that it’s not true that n is either true or not true.
But here’s
my problem. If I deny (1) by affirming
(2) ~(x)(Tx v
~Tx)
I thereby affirm
(3) (∃x)(~Tx • Tx)
for (2) and (3) are logically equivalent if quantifier
negation and De Morgan’s law are valid, which they are. So here’s my dilemma:
affirm (1) or affirm a contradiction. Because (1) itself will eventually lead
to a contradiction, my choice is really between affirming a contradiction now
or affirming one later. I choose never. So I say that though (1) and (2) appear
to be more than a string of symbols, they are not.
Sunday, May 24, 2015
on whether a string of bananas may refer to itself.
The following sentence may express a truth when you use it:
This string of symbols per se does not refer to itself.
But if you proceed to mention the previous sentence and affirm
that at it is true, the previous sentence is no longer being used but rather is being referred to,
in which case you are, in effect, declaring that a string of symbols is true.
But how can a string of symbols not only express
a truth, but also be true? I
understand, for example, how an arrangement of bananas may express a truth, but
what does it mean to say that the arrangement of bananas would thereby itself be true?
That * is bananas.
Saturday, May 23, 2015
on whether every thesis should be examined.
“Not every problem, or every thesis,
should be examined, but only one which might puzzle one of those who need
argument, not punishment or perception. For people who are puzzled to know
whether one ought to honor the gods and love one’s parents or not need
punishment, while those who are puzzled to know whether snow is white or not need
perception.”
Aristotle, Topics I, 11, 105a2-8
on the purpose of words.
“…But it should make no difference
whichever description is used; for our object in thus distinguishing them has
not been to create a new terminology, but to recognize what differences
actually exists between them.”
Aristotle, Topics I, 11,
104a137ish
Saturday, May 16, 2015
Quine is right only if Quine is wrong.
“…necessity resides in the way in which we say things, and not
in the things we talk about.”
– W.V. Quine, “Three
grades of modal involvement”
(note: in what follows I use single-quotation marks to name
words and ignore their meaning and double-quotation marks to name a word with
emphasis on its meaning.)
Suppose I ask you if the statement
(1)
Brutus killed Caesar.
could have been false, and you say: “Yes, for the word
‘killed’ could have meant “married”, and since Brutus did not marry Caesar, had
(1) meant “Brutus married Caesar”, (1) would have been false.”
Utterly
dumbfounded by your response, I present you with the following statement
(2)
7 is
prime.
and ask if (2) could have been false, and you respond in
kind: “Yes, for the word ‘7’ could have meant “6”, and since 6 is not prime,
had (2) meant “6 is prime”, (2) would have been false.”
At this
point exactly half of my dumbfoundery has vanished because I see that when I
asked you whether (1) and (2) could have been false, you responded by mentioning
the words I used when I was using those words to talk about things.
Suppose I
make the semantic ascent to your level and ask you if you think it’s true that:
(3)
The word
‘killed’ could have meant “married”.
and
(4)
The word
‘7’ could have meant “6”.
If you answer “no”, then you’re being inconsistent. If you answer “yes”, then you disagree with
Quine, for (3) and (4) are true only if necessity resides in at least some of
things we talk about, for (3) and (4) are equivalent to
(3’) The
word ‘killed’ possibly means “married”.
and
(4’) The
word ‘7’ possibly means “6”.
and (3’) and (4’) are equivalent to
(3’’) The
word ‘killed’ doesn’t necessarily not mean “married”.
(4’’) The
word ‘7’ doesn’t necessarily not mean “6”.
Ergo, etc.
Friday, May 15, 2015
on the usefulness of a quine.
quine, n. a razor-sharp machete often used to
shave beards and clear jungles. Usually too blunt for either task, but quite
effective for precision trimming and stunting overgrowth.
Thursday, May 14, 2015
you may use one but don't mention it.
At t1, I come into existence and
say nothing. At t2 I say,
“the cat is on mat” and nothing else. But, at t2, the cat is not on the mat. At t3, I say, “I never tell the truth” and nothing else. What exactly am I saying? Here are some
options:
(1) What I said at t2 is true.
(2) What I said at t2 is not true.
(3) What I said at t2 is true and what I am saying at t3
is true.
(4) What I said at t2 is true and what I am saying at t3
is not true.
(5) What I said at t2 is not true and what I am saying at t3
is true.
(6) What I said at t2 is not true and what I am saying at t3
is not true.
If (1), then what I say is false, full stop.
If (2), then what I say is true, full stop.
If (3), then what I say is false, full stop.
If (4), then what I say is false, full stop.
If (5), then what I say is true, full stop.
If (6), then what I say is false, full stop.
Are there any other options?
If not, whatever it is I say at t3,
it is not both true and false. Ergo, etc.
Wednesday, May 13, 2015
at least two formally valid arguments are not valid.
Here’s a formal proof of the liar:
1. (x)(p)((Cx
• Sx(p)) ⊃ ~p)
2. Cc • Sc((x)(Cx • Sx(p) ⊃ ~p)) ∴ ~(x)(p)((Cx
• Sx(p)) ⊃ ~p)
3. Cc • Sc((x)(p)((Cx • Sx(p)) ⊃
~p) ⊃ ~(x)(p)((Cx • Sx(p)) ⊃ ~p 1, UI
4.
~(x)(p)((Cx • Sx(p)) ⊃
~p) 2, 3, MP
In English:
1. for any x and any p if x is a Cretan and x says p then ~p.
2. Chris is a Cretan and Chris says for
any x and any p if x is a Cretan and x says p then ~p.
3. If Chris is a Cretan and Chris says
for any x and any p if x is a Cretan and x says p then ~p then it’s not
the case that for any x and any p if x is a Cretan and x says p then ~p. (From 1 and universal instantiation)
4. it’s not the case that for any x and any p if x is a Cretan and x says p then ~p. (from 2, 3,
and modus ponens)
Here might be a way out:
The argument’s form is valid, but there is no time in which the string of symbols
which compose lines 1 and 2 express a proposition. Since strings of symbols
which fail to express propositions eo
ipso fail to express premises, any instance of lines 1 and 2 will fail to
constitute an argument. Since only
arguments may be valid and lines 1 and 2 fail to constitute an argument,
nothing follows from lines 1 and 2.
Ergo, there is no liar’s paradox.
Objection: Wow. Way to be ad hoc.
Reply: False. I have independent
reasons for saying that some strings of symbols which appear to express
propositions don’t actually express propositions. For example, here’s a formal
proof of Zeus’ existence:
1. (x)x
= x
∴ (∃x)x
= z
2. z = z 1, UI
3. (∃x)x = z 2, EG
In English:
1. Everything is identical to itself.
2. Zeus is Zeus. (from 1 and universal instantiation)
3. There is something such that it is
Zeus. (from 2, and existential
generalization)
I think that this argument’s form is
valid, and I also think that its one and only premise is true. However, I don’t
think the string of symbols in line 2 expresses a proposition because in order
for it to express a proposition, the letter ‘z’ must refer to Zeus. Since Zeus
doesn’t exist, ‘z’ doesn’t name
anything, and therefore line 2 is not even false. Since the proof only goes
through if each line expresses a proposition, lines 1, 2, and 3 fail to
constitute a proof.
on dubious business.
W.V. Quine (1974, p. 187f) says
that quantifying into intensional contexts is dubious business, and he offers
the following as a case in point. Ralph suspects that the man wearing a green hat
is a spy. Though they have never met, Ralph has also heard a great deal of good
about a fellow by the name of Bernard. Unbeknownst to Ralph, the man in the green
hat and Bernard are one and the same person. We ask Ralph about whether he thinks
Bernard is a spy, and Ralph replies, “Bernard is no spy!” Thus, it appears that
Ralph has contradictory beliefs: Ralph believes that Bernard is a spy and Ralph
believes that Bernard is not a spy.
Wait, what?
This isn’t obvious. It seems to me that Ralph believes that someone who wears a
green hat is a spy: (let ‘r’ abbreviate ‘Ralph’ and ‘(∃x)Br(Sx • Gx)’ abbreviate ‘there
is something such that Ralph believes it is a spy and it wears a green hat’.
Thus:
(1) (∃x)Br(Sx • Gx)
Ralph also believes that Bernard (b) is not a spy:
(2) (∃x)Br(x = b • ~Sx)
(1) and (2) quantify into Ralph’s beliefs, but their conjunction
does not imply that Ralph has contradictory beliefs.
References
Quine, W.V. (1974) “Quantifiers and Propositional
Attitudes”, reprinted in The Ways of Paradox and
Other Essays (revised ed.), Cambridge: Harvard University Press.
This work is licensed under a Creative Commons Attribution-NonCommercial-NoDerivs 3.0 United States License.